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Qno14:- Sides AB and AC and median AD of a ∆ABC are respectively proportional to sides PQ and PR and median PM of another ∆PQR۔ Show that ∆ABC ~PQR۔

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mathslab98.blogspot.com Qno14:- Sides AB and AC and median AD of a ∆ABC are respectively  proportional to sides PQ and PR and median PM of another ∆PQR۔ Show that ∆ABC ~PQR۔ Given: AB/PQ=AC/PR=AD/PM۔ and In ∆ABC, AD is the median. • BD = DC Also in ∆PQR, PM is the median. • QM= MR۔ Construction: in ∆ABC Draw DG || AC and DE || AB۔ Also in ∆PQR Draw FM || PR and HM|| PQ۔ To Prove:- ∆ABC ~ ∆PQR۔ Proof:-  Since D is the mid point of BC and DG || AC. So by Converse of Mid Point Theorem. The converse of midpoint theorem states that: "If a line segment is drawn  passing  through the midpoint of any one side of a triangle and  parallel  to another side, then this line segment  bisects  the remaining third side.  i,e DG bisects AB. => AG = BG Similarly  AE = EC Also in ∆PQR ; PF = FQ  and PH = HR Now in ∆ABC ; GD || AE and AG|| DE => Quadrilateral AGDE is a Parallelogram . Then  GE = AE ..........1. ( Opposite sides of ||gm are equal) similarly in ∆PQR ; F

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