MEHRAJ AFZAL

  Virat Kohli vs. Sam Konstas: The Spark That Lit Up Today’s Test Match Cricket is more than just a sport; it’s a stage where characters collide, temperaments are tested, and stories are written. In today’s thrilling Test match, the spotlight fell on two contrasting figures—Indian cricket’s fiery maestro Virat Kohli and Australia’s young debutant Sam Konstas . What unfolded was a masterclass in aggression, composure, and the essence of Test cricket itself. Virat Kohli: The Art of Commanding the Stage Virat Kohli is not just a cricketer; he is a phenomenon. Known for his unrelenting passion, he has the rare ability to turn a cricket field into his personal theatre. Today, Kohli was at his aggressive best—his every action a declaration of intent. Whether orchestrating the field placements, engaging in sharp banter with the opposition, or dominating with the bat, Kohli was a man on a mission. His aggression wasn’t chaotic; it was calculated, serving as a rallying cry for his tea...

mathslab98.blogspot.com Qno14:- Sides AB and AC and median AD of a ∆ABC are respectively  proportional to sides PQ and PR and median PM of another ∆PQR۔ Show that ∆ABC ~PQR۔ Given: AB/PQ=AC/PR=AD/PM۔ and In ∆ABC, AD is the median. • BD = DC Also in ∆PQR, PM is the median. • QM= MR۔ Construction: in ∆ABC Draw DG || AC and DE || AB۔ Also in ∆PQR Draw FM || PR and HM|| PQ۔ To Prove:- ∆ABC ~ ∆PQR۔ Proof:-  Since D is the mid point of BC and DG || AC. So by Converse of Mid Point Theorem. The converse of midpoint theorem states that: "If a line segment is drawn  passing  through the midpoint of any one side of a triangle and  parallel  to another side, then this line segment  bisects  the remaining third side.  i,e DG bisects AB. => AG = BG Similarly  AE = EC Also in ∆PQR ; PF = FQ  and PH = HR Now in ∆ABC ; GD || AE and AG|| DE => Quadrilateral AGDE is a Parallelogram . Then  GE = AE ..........1. ( Opp...

JKBOSE MATHEMATICS